Solution
Let us draw a table according to the information given.
It is given that the numbers of bureaucrats in the research and teaching committees are equal, while the number of bureaucrats in the research committee is 75% of the number of bureaucrats in the administration committee. Let '4x' be the number of bureaucrats in Administration committee.
The number of educationalists in the teaching committee is less than the number of educationalists in the research committee. The number of educationalists in the research committee is the average of the numbers of educationalists in the other two committees. Let us assume that 'y' is the number of educationalists in the research committee and 'd' be the difference in the number of educationalists in Research and teaching committees.
60% of the politicians are in the administration committee, and 20% are in the teaching committee. Let '5z' be the number of total number of politicians.
We can say that
$$\Rightarrow$$ 10x+3y+5z = 24
We can see that each of x, y and z has to a natural number integer. If x > 1, then both y and z can't take any natural number.
Hence, we can say that x = 1.
At x = 1, 3y+5z = 14. If y = 1 or 2, Z is not an integer.
At x = 1 and y = 3, z = 1 which is the only possible solution.
We can see that 'd' can assume two possible values. d = 1 or 2.
From the table, we can see that the number of bureaucrats in the administration committee = 4.