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Q1:

2025 Slot 3

Progression & Series

Medium

In an arithmetic progression, if the sum of fourth, seventh and tenth terms is 99, and the sum of the first fourteen terms is 497, then the sum of first five terms is

65
Correct Answer
Explanation for 2025 Slot 3 QA question 1

Q2:

2025 Slot 2

Progression & Series

Medium

Let ana_n be the nthn^{th} term of a decreasing infinite geometric progression. If a1+a2+a3=52a_1+a_2+a_3 = 52 and a1a2+a2a3+a3a1=624a_1a_2+a_2a_3+a_3a_1 = 624, then the sum of this geometric progression is

Answer options
Option 3
Correct Answer
Explanation for 2025 Slot 2 QA question 2

Q3:

2025 Slot 1

Progression & Series

Medium

In the set of consecutive odd numbers {1,3,5,…,57}\{1, 3, 5, \ldots, 57\}, there is a number kk such that the sum of all the elements less than kk is equal to the sum of all the elements greater than kk. Then, kk equals

Answer options
Option 1
Correct Answer
Explanation for 2025 Slot 1 QA question 3

Q4:

2025 Slot 1

Progression & Series

Hard

For any natural number kk, let ak=3ka_k = 3^k. The smallest natural number mm for which {(a1)1×(a2)2×…×(a20)20}<{a21×a22×…×a(20+m)}\{(a_1)^1 \times (a_2)^2 \times \ldots \times (a_{20})^{20}\} < \{a_{21} \times a_{22} \times \ldots \times a_{(20+m)}\}, is

Answer options
Option 3
Correct Answer
Explanation for 2025 Slot 1 QA question 4

Q5:

CAT 2024 Slot 3

Progression & Series

Medium

Consider the sequence t1=1t_1 = 1, t2=−1t_2 = -1 and tn=(n−3n−1)tn−2t_n = \left(\frac{n-3}{n-1}\right) t_{n-2} for n≥3n \ge 3. The, the value of the sum 1t2+1t4+1t6+⋯+1t2022+1t2024\frac{1}{t_2} + \frac{1}{t_4} + \frac{1}{t_6} + \dots + \frac{1}{t_{2022}} + \frac{1}{t_{2024}} is

Answer options
Option 3
Correct Answer
Explanation for CAT 2024 Slot 3 QA question 5

Q6:

CAT 2024 Slot 2

Progression & Series

Medium

The sum of the infinite series is 15(15−17)+(15)2((15)2−(17)2)+(15)3((15)3−(17)3)+….\frac{1}{5}\left(\frac{1}{5}-\frac{1}{7}\right)+\left(\frac{1}{5}\right)^{2}\left(\left(\frac{1}{5}\right)^{2}-\left(\frac{1}{7}\right)^{2}\right)+\left(\frac{1}{5}\right)^{3}\left(\left(\frac{1}{5}\right)^{3}-\left(\frac{1}{7}\right)^{3}\right)+\ldots .. equal to

Answer options
Option 1
Correct Answer
Explanation for CAT 2024 Slot 2 QA question 6

Q7:

CAT 2024 Slot 1

Progression & Series

Medium

Suppose x1,x2,x3,…,x100x_{1}, x_{2}, x_{3}, \ldots, x_{100} are in arithmetic progression such that x5=−4x_{5}=-4 and 2x6+2x9=x11+x132 x_{6}+2 x_{9}=x_{11}+x_{13}, Then, x100x_{100} equals

Answer options
Option 2
Correct Answer
Explanation for CAT 2024 Slot 1 QA question 7

Q8:

CAT 2023 Slot 3

Progression & Series

Hard

The value of 1+(1+13)14+(1+13+19)116+(1+13+19+127)164+……1+\left(1+\frac{1}{3}\right) \frac{1}{4}+\left(1+\frac{1}{3}+\frac{1}{9}\right) \frac{1}{16}+\left(1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\right) \frac{1}{64}+\ldots \ldots, is

Answer options
Option 3
Correct Answer
Explanation for CAT 2023 Slot 3 QA question 8

Q9:

CAT 2023 Slot 3

Progression & Series

Medium

Let an=46+8na_n = 46 + 8n and bn=98+4nb_n = 98 + 4n be two sequences for natural numbers n≤100n \le 100. Then, the sum of all terms common to both the sequences is

Answer options
Option 2
Correct Answer
Explanation for CAT 2023 Slot 3 QA question 9

Q10:

CAT 2023 Slot 2

Progression & Series

Medium

Let both the series a1,a2,a3,…a_1, a_2, a_3, \dots and b1,b2,b3…b_1, b_2, b_3 \dots be in arithmetic progression such that the common differences of both the series are prime numbers. If a5=b9a_5 = b_9, a19=b19a_{19} = b_{19} and b2=0b_2 = 0, then a11a_{11} equals

Answer options
Option 1
Correct Answer
Explanation for CAT 2023 Slot 2 QA question 10

Q11:

CAT 2023 Slot 2

Progression & Series

Medium

Let ana_n and bnb_n be two sequences such that an=13+6(n−1)a_n = 13 + 6 (n - 1) and bn=15+7(n−1)b_n = 15 + 7 (n - 1) for all natural numbers nn. Then, the largest three digit integer that is common to both these sequences, is

Q12:

CAT 2023 Slot 1

Progression & Series

Medium

For some positive and distinct real numbers x,yx, y and zz, if 1y+z\frac{1}{\sqrt{y}+\sqrt{z}} is the arithmetic mean of 1x+z\frac{1}{\sqrt{x}+\sqrt{z}} and 1x+y\frac{1}{\sqrt{x}+\sqrt{y}}, then the relationship which will always hold true, is

Answer options
Option 1
Correct Answer
Explanation for CAT 2023 Slot 1 QA question 12

Q13:

CAT 2023 Slot 1

Progression & Series

Medium

A lab experiment measures the number of organisms at 88 am every day. Starting with 22 organisms on the first day, the number of organisms on any day is equal to 33 more than twice the number on the previous day. If the number of organisms on nth day exceeds one million, then the lowest possible value of nn is

Q14:

CAT 2022 Slot 3

Progression & Series

Medium

The average of all 3-digit terms in the arithmetic progression 38,55,72,…38, 55, 72, \dots, is

Q15:

CAT 2022 Slot 2

Progression & Series

Medium

On day one, there are 100100 particles in laboratory experiment. On day nn, where n≥2n \geq 2, one out of every nn particles produces another particle. If the total number of particles in the laboratory experiment increases to 10001000 on day mm, then mm equals.

Answer options
Option 1
Correct Answer
Explanation for CAT 2022 Slot 2 QA question 15

Q16:

CAT 2022 Slot 2

Progression & Series

Hard

The average of a non-decreasing sequence of NN numbers a1,a2,…,aNa_{1}, a_{2}, \ldots, a_{N} is 300300. If a1a_{1} is replaced by 6a16 a_{1}, the new average becomes 400400. Then, the number of possible values of a1a_{1} is

Q17:

CAT 2022 Slot 2

Progression & Series

Medium

Consider the arithmetic progression 3, 7, 11, ..... and let Aₙ denote the sum of the first n terms of this progression. Then the value of 125∑n=125An\frac{1}{25} \sum_{n=1}^{25} A_n is

Answer options
Option 3
Correct Answer
Explanation for CAT 2022 Slot 2 QA question 17

Q18:

CAT 2022 Slot 1

Progression & Series

Medium

For any natural number n, suppose the sum of the first n terms of an arithmetic progression is (n+2n2)(n + 2n^2). If the nthn^{th} term of the progression is divisible by 99, then the smallest possible value of nn is

Answer options
Option 2
Correct Answer
Explanation for CAT 2022 Slot 1 QA question 18

Q19:

CAT 2021 Slot 3

Progression & Series

Medium

If n is a positive integer such that (107)(107)2…(107)n>999(\sqrt[7]{10})(\sqrt[7]{10})^{2} \ldots(\sqrt[7]{10})^{n}>999, then the smallest value of n is

Q20:

CAT 2021 Slot 3

Progression & Series

Medium

Consider a sequence of real number x1,x2,x3,...x_1, x_2, x_3, ... such that xn+1=xn+n−1x_{n+1} = x_n + n - 1 for all n≥1n \ge 1. If x1=−1x_1 = -1 then x100x_{100} is equal to

Answer options
Option 2
Correct Answer
Explanation for CAT 2021 Slot 3 QA question 20

Q21:

CAT 2021 Slot 2

Progression & Series

Medium

Three positive integers x,yx, y and zz are in arithmetic progression. If y−x>2y − x > 2 and xyz=5(x+y+z)xyz = 5(x + y + z), then z−xz − x equals

Answer options
Option 1
Correct Answer
Explanation for CAT 2021 Slot 2 QA question 21

Q22:

CAT 2021 Slot 2

Progression & Series

Medium

For a sequence of real numbers x1,x2,......xnx_1, x_2, ...... x_n, if x1−x2+x3−....+(−1)n+1xn=n2+2nx_1 - x_2 + x_3 - .... + (-1)^{n + 1} x_n = n^2 + 2n for all natural numbers n, then the sum x49+x50x_{49} + x_{50} equals

Answer options
Option 2
Correct Answer
Explanation for CAT 2021 Slot 2 QA question 22

Q23:

CAT 2021 Slot 1

Progression & Series

Medium

If x0=1,x1=2\mathrm{x}_{0}=1, \mathrm{x}_{1}=2, and xn+2=1+xn+1xn,n=0,1,2,3……\mathrm{x}_{\mathrm{n}+2}=\frac{1+x_{n+1}}{x_{n}}, n=0,1,2,3 \ldots \ldots., then x2021x_{2021} is

Answer options
Option 2
Correct Answer
Explanation for CAT 2021 Slot 1 QA question 23

Q24:

CAT 2021 Slot 1

Progression & Series

Medium

The natural numbers are divided into groups as (1), (2,3,4),(5,6,7,8,9),….(2,3,4),(5,6,7,8,9), \ldots .. and so on. Then, the sum of the numbers in the 15th group is equal to

Answer options
Option 1
Correct Answer
Explanation for CAT 2021 Slot 1 QA question 24

Q25:

CAT 2020 Slot 3

Progression & Series

Medium

If x1=−1x_1 = -1 and xm=xm+1+(m+1)x_m = x_{m+1} + (m + 1) for every positive integer m,m, then x100x_{100} equals

Answer options
Option 3
Correct Answer
Explanation for CAT 2020 Slot 3 QA question 25

Q26:

CAT 2020 Slot 2

Progression & Series

Hard

Let the mthm^{th} and nthn^{th} terms of a geometric progression be 3/43 / 4 and 1212, respectively, where m<nm<n. If the common ratio of the progression is an integer rr, then the smallest possible value of r+n−mr+n-m is

Answer options
Option 1
Correct Answer
Explanation for CAT 2020 Slot 2 QA question 26

Q27:

CAT 2019 Slot 2

Progression & Series

Medium

Let a1,a2,...a_1, a_2, ... be integers such that a1−a2+a3−a4+...+(−1)n−1an=na_1 - a_2 + a_3 - a_4 + ... + (-1)^{n - 1} a_n = n, for all n≥1n \ge 1. Then a51+a52+...+a1023a_{51} + a_{52} + ... + a_{1023} equals

Answer options
Option 2
Correct Answer
Explanation for CAT 2019 Slot 2 QA question 27

Q28:

CAT 2019 Slot 2

Progression & Series

Medium

The number of common terms in the two sequences: 15,19,23,27,.......,41515, 19, 23, 27,......., 415 and 14,19,24,29,........,46414, 19, 24, 29,........,464 is

Answer options
Option 2
Correct Answer
Explanation for CAT 2019 Slot 2 QA question 28

Q29:

CAT 2019 Slot 2

Progression & Series

Medium

If (2n+1)+(2n+3)+(2n+5)+....+(2n+47)=5280(2n + 1) + (2n + 3) + (2n + 5) + .... + (2n + 47) = 5280, then what is the value of 1+2+3+...+n1 + 2 + 3 + ... + n?

Q30:

CAT 2019 Slot 1

Progression & Series

Easy

If a1+a2+a3+⋯+an=3×(2n+1−2)a_1 + a_2 + a_3 + \dots + a_n = 3 \times (2^{n+1} - 2), for every n≥1n \ge 1, then a11a_{11} equals