CATAlgebra > HardEntered answer:✅ Correct Answer: 19Related questions:CAT 2019 Slot 1If a1+a2+a3+⋯+an=3×(2n+1−2)a_1 + a_2 + a_3 + \dots + a_n = 3 \times (2^{n+1} - 2)a1+a2+a3+⋯+an=3×(2n+1−2), for every n≥1n \ge 1n≥1, then a11a_{11}a11 equalsCAT 2017 Slot 2An infinite geometric progression a1,a2,a3,...a_1, a_2, a_3,...a1,a2,a3,... has the property that an=3(an+1+an+2+....)a_n = 3(a_{n+1} + a_{n+2} +....)an=3(an+1+an+2+....) for every n≥1n \ge 1n≥1. If the sum a1+a2+a3+.....=32a_1 + a_2 + a_3 +..... = 32a1+a2+a3+.....=32, then a5a_5a5 isCAT 2017 Slot 1Let a1,a2,……...a3na_{1}, a_{2}, \ldots \ldots . . . a_{3 n}a1,a2,……...a3n be an arithmetic progression with a1=3a_{1}=3a1=3 and a2=7a_{2}=7a2=7. If a1+a2+….+a3n=1830a_{1}+a_{2}+\ldots .+a_{3 n}=1830a1+a2+….+a3n=1830, then what is the smallest positive integer mmm such that m(a1+a2+….+an)>1830m\left(a_{1}+a_{2}+\ldots .+a_{n}\right)>1830m(a1+a2+….+an)>1830 ?