CATAlgebra > Medium150001500015000149001490014900146021460214602147981479814798✅ Correct Option: 2Related questions:CAT 2024 Slot 2The sum of the infinite series is 15(15−17)+(15)2((15)2−(17)2)+(15)3((15)3−(17)3)+….\frac{1}{5}\left(\frac{1}{5}-\frac{1}{7}\right)+\left(\frac{1}{5}\right)^{2}\left(\left(\frac{1}{5}\right)^{2}-\left(\frac{1}{7}\right)^{2}\right)+\left(\frac{1}{5}\right)^{3}\left(\left(\frac{1}{5}\right)^{3}-\left(\frac{1}{7}\right)^{3}\right)+\ldots .51(51−71)+(51)2((51)2−(71)2)+(51)3((51)3−(71)3)+….. equal toCAT 2021 Slot 2Three positive integers x,yx, yx,y and zzz are in arithmetic progression. If y−x>2y − x > 2y−x>2 and xyz=5(x+y+z)xyz = 5(x + y + z)xyz=5(x+y+z), then z−xz − xz−x equalsCAT 2017 Slot 2An infinite geometric progression a1,a2,a3,...a_1, a_2, a_3,...a1,a2,a3,... has the property that an=3(an+1+an+2+....)a_n = 3(a_{n+1} + a_{n+2} +....)an=3(an+1+an+2+....) for every n≥1n \ge 1n≥1. If the sum a1+a2+a3+.....=32a_1 + a_2 + a_3 +..... = 32a1+a2+a3+.....=32, then a5a_5a5 is