Skip to main contentSkip to solution

The number of coins collected per week by two coin-collectors AA and BB are In the ratio 3:43:4. If the total number of coins collected by AA in 55 weeks is a multiple of 77, and the total number of coins collected by BB in 33 weeks is a multiple of 2424, then the minimum possible number of coins collected by AA in one week is

Entered answer:

Solution

✅ Correct Answer: 42

We break down what we know:

Two coin collectors A and B collect coins each week. Their collection rates are in the ratio 3:4. A's total collection in 5 weeks is a multiple of 7. B's total collection in 3 weeks is a multiple of 24.


When we say A and B collect coins in the ratio 3:4, this means:

If A collects 3 coins per week, then B collects 4 coins per week. If A collects 6 coins per week, then B collects 8 coins per week. And so on...

The key insight: We can represent their weekly collections as:

A collects 3x coins per week

B collects 4x coins per week

where x is some positive whole number that maintains the 3:4 ratio.


Now we calculate their total collections over multiple weeks:

A's collection in 5 weeks: 5×3x=15x5 \times 3x = 15x coins

B's collection in 3 weeks: 3×4x=12x3 \times 4x = 12x coins


A number is a multiple of 7 if it can be written as 7×7 \times (some whole number).

Examples: 7, 14, 21, 28, 35...

A number is a multiple of 24 if it can be written as 24×24 \times (some whole number).

Examples: 24, 48, 72, 96...


Condition 1: 15x15x is a multiple of 7

This means 15x=7k15x = 7k for some whole number k.

Since 15 and 7 share no common factors (they are coprime), x itself must be a multiple of 7.

Condition 2: 12x12x is a multiple of 24

This means 12x=24m12x = 24m for some whole number m.

Dividing both sides by 12: x=2mx = 2m

This tells us x must be even (divisible by 2).


We need x to satisfy both conditions:

x must be a multiple of 7

x must be even

The smallest positive number that is both a multiple of 7 and even is 14.

We verify:

Is 14 a multiple of 7? Yes: 14=7×214 = 7 \times 2

Is 14 even? Yes: 14=2×714 = 2 \times 7


With x=14x = 14:

A collects 3x=3×14=423x = 3 \times 14 = 42 coins per week

We check:

A in 5 weeks: 42×5=21042 \times 5 = 210 coins (210÷7=30210 \div 7 = 30, so it's a multiple of 7)

B in 3 weeks: 56×3=16856 \times 3 = 168 coins (168÷24=7168 \div 24 = 7, so it's a multiple of 24)

Therefore, the minimum possible number of coins collected by A in one week is 42.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question