CATAlgebra > Medium200200200−2-2−2222−200-200−200✅ Correct Option: 2Related questions:CAT 2019 Slot 2If (2n+1)+(2n+3)+(2n+5)+....+(2n+47)=5280(2n + 1) + (2n + 3) + (2n + 5) + .... + (2n + 47) = 5280(2n+1)+(2n+3)+(2n+5)+....+(2n+47)=5280, then what is the value of 1+2+3+...+n1 + 2 + 3 + ... + n1+2+3+...+n?CAT 2024 Slot 3Consider the sequence t1=1t_1 = 1t1=1, t2=−1t_2 = -1t2=−1 and tn=(n−3n−1)tn−2t_n = \left(\frac{n-3}{n-1}\right) t_{n-2}tn=(n−1n−3)tn−2 for n≥3n \ge 3n≥3. The, the value of the sum 1t2+1t4+1t6+⋯+1t2022+1t2024\frac{1}{t_2} + \frac{1}{t_4} + \frac{1}{t_6} + \dots + \frac{1}{t_{2022}} + \frac{1}{t_{2024}}t21+t41+t61+⋯+t20221+t20241 isCAT 2017 Slot 1Let a1,a2,……...a3na_{1}, a_{2}, \ldots \ldots . . . a_{3 n}a1,a2,……...a3n be an arithmetic progression with a1=3a_{1}=3a1=3 and a2=7a_{2}=7a2=7. If a1+a2+….+a3n=1830a_{1}+a_{2}+\ldots .+a_{3 n}=1830a1+a2+….+a3n=1830, then what is the smallest positive integer mmm such that m(a1+a2+….+an)>1830m\left(a_{1}+a_{2}+\ldots .+a_{n}\right)>1830m(a1+a2+….+an)>1830 ?