Two pipes and are attached to an empty water tank. Pipe fills the tank while pipe drains it. If pipe is opened at pm and pipe is opened at pm , then the tank becomes full at . Instead, if pipe is opened at and pipe is opened at , then the tank becomes full at . If pipe is not opened at all, then the time, in minutes, taken to fill the tank is
Two pipes and are attached to an empty water tank. Pipe fills the tank while pipe drains it. If pipe is opened at pm and pipe is opened at pm , then the tank becomes full at . Instead, if pipe is opened at and pipe is opened at , then the tank becomes full at . If pipe is not opened at all, then the time, in minutes, taken to fill the tank is
Solution
We have two pipes working on a water tank:
Pipe A: Fills the tank (positive work)
Pipe B: Drains the tank (negative work)
The key insight is that when both pipes work together, the net filling rate = Rate of A - Rate of B
Case 1: A opens at 2pm, B opens at 3pm, tank full at 10pm
Pipe A works: 2pm to 10pm = 8 hours
Pipe B works: 3pm to 10pm = 7 hours
Result: Tank becomes full
Case 2: A opens at 2pm, B opens at 4pm, tank full at 6pm
Pipe A works: 2pm to 6pm = 4 hours
Pipe B works: 4pm to 6pm = 2 hours
Result: Tank becomes full
Instead of setting up complex equations, let's compare what changed between the two cases:
What changed from Case 1 to Case 2?
Pipe B worked 5 hours less (from 7 hours to 2 hours)
Pipe A worked 4 hours less (from 8 hours to 4 hours)
Key Insight: When pipe B works 5 hours less, pipe A needs to work 4 hours less to achieve the same result (full tank).
This tells us the relationship between their rates:
5 hours less of B's draining = 4 hours less of A's filling needed
Ratio discovered: 1 hour less of B's work = hours less of A's work
Now, what if B doesn't work at all?
In Case 1, B worked for 7 hours
If B doesn't work at all, that's 7 hours less of B's work
Time saved for A = hours
Therefore: A alone would take hours
Converting to minutes: minutes
This approach works because we're using the principle of equivalent work. When we reduce one pipe's work time, we can calculate how much the other pipe's work time changes to maintain the same net result.
This is much faster than solving simultaneous equations, and it directly gives us the relationship between the two pipes' efficiencies.
Answer: 144 minutes