CATAlgebra > Medium[37,12][\frac{3}{7}, \frac{1}{2}][73,21][37,12)[\frac{3}{7}, \frac{1}{2})[73,21)[37,92)[\frac{3}{7}, \frac{9}{2})[73,29)[49,89][\frac{4}{9}, \frac{8}{9}][94,98]✅ Correct Option: 2Related questions:CAT 2023 Slot 3Suppose f(x,y)f(x, y)f(x,y) is a real valued function such that f(3x+2y,2x−5y)=19xf(3x + 2y, 2x- 5y) = 19xf(3x+2y,2x−5y)=19x, for all real numbers xxx and yyy. The value of xxx for which f(x,2x)=27f(x, 2x) = 27f(x,2x)=27, isCAT 2019 Slot 1Consider a function fff satisfying f(x+y)=f(x)f(y)f(\mathrm{x}+\mathrm{y})=f(\mathrm{x}) \mathrm{f}(\mathrm{y})f(x+y)=f(x)f(y) where x,yx , yx,y are positive integers, and f(1)=2f(1)=2f(1)=2. If f(a+1)+f(a+2)+……+f(a+n)=f(\mathrm{a}+1)+f(\mathrm{a}+2)+\ldots \ldots+f(\mathrm{a}+\mathrm{n})=f(a+1)+f(a+2)+……+f(a+n)= 16(2n−1)16\left(2^{n}-1\right)16(2n−1) then a is equal toCAT 2018 Slot 1If f(x+2)=f(x)+f(x+1)f(x + 2) = f(x) + f(x + 1)f(x+2)=f(x)+f(x+1) for all positive integers xxx, and f(11)=91f(11) = 91f(11)=91, f(15)=617f(15) = 617f(15)=617, then f(10)f(10)f(10) equals