Solution
Understanding the set :-
This is a minima maxima + quantitative set :
Here you have 100 boxes and a mystery prices in every box, named as a, b, c...
Also, it is given that, there is price of item a is highest , then prices b, then price c, and so on...
Price a - a diamond ring is only in one of the box,
and other prices are atleast double in quantity of previous item i.e.,
we know item a is only 1 , then item b will be atleast two and item c will again be atleast double of item b.
Now, lets try to solve the set with the given information -
Now as per the additional information given in the question, there are a total of 75 boxes in which the same item is given
(one in box number 45 and 31 items in 1 - 44 boxes and 43 items in 46 - 100 boxes).
Now the remaining 25 items has to be maximized in terms of variety.
There is 1 item of type A, so let there be 2 items of type B, 4 items of type C, 8 items of type D.
Now after that if try to have 32 items of type E, the total items become more than 100.
Thus there can be only 4 more types of items other than the one, which has been used in box number 45.
So the total different types of items at the most can be 5.