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If xx and yy are non-negative integers such that x+9=z,y+1=zx+9=z, y+1=z and x+y<z+5x+y<z+5, then the maximum possible value of 2x+y2 x+y ?

Entered answer:

Solution

✅ Correct Answer: 23

We're given three key pieces of information:

x+9=zx + 9 = z ... (equation 1)

y+1=zy + 1 = z ... (equation 2)

x+y<z+5x + y < z + 5 ... (inequality)

Key insight: Since both x+9x + 9 and y+1y + 1 equal zz, we can use this to connect xx and yy.


From equations (1) and (2):

x=z−9x = z - 9

y=z−1y = z - 1

Adding these equations together:

(x+9)+(y+1)=z+z(x + 9) + (y + 1) = z + z

x+y+10=2zx + y + 10 = 2z

Therefore: x+y=2z−10x + y = 2z - 10

This expresses x+yx + y in terms of zz only, which will help us use the inequality.


We know that x+y<z+5x + y < z + 5

Substituting our expression for x+yx + y:

2z−10<z+52z - 10 < z + 5

2z−z<5+102z - z < 5 + 10

z<15z < 15

Since zz must be an integer and z<15z < 15, the maximum possible value is z=14z = 14.


Once we know z=14z = 14:

From equation (1): x=z−9=14−9=5x = z - 9 = 14 - 9 = 5

From equation (2): y=z−1=14−1=13y = z - 1 = 14 - 1 = 13

Let's check our constraint x+y<z+5x + y < z + 5:

5+13=185 + 13 = 18 and 14+5=1914 + 5 = 19

Indeed, 18<1918 < 19


Maximum value of 2x+y=2(5)+13=10+13=232x + y = 2(5) + 13 = 10 + 13 = 23


The key insight is that to maximize 2x+y2x + y, we need to maximize both xx and yy. Since both xx and yy increase as zz increases, we want the largest possible zz that satisfies our constraints.

The maximum possible value of 2x+y2x + y is 23.

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