Solution
Understanding the set :-
- This is a routes and networks set, in this type of set you basically get some junction points and multiple routes to reach that point
- In this type of set, after getting a broad idea of the details and clues (if given), will mainly be based on questions of the set.
- In this particular question, we are given metro lines (routes) with their stations (junctions).
- Also, Each train runs either in east-west or north-south direction, but not both
Let’s try to simplify the set using clues given
Clues given to us :-
- All trains stop for 2 minutes at each of the junction stations on the way and for 1 minute at each of the other stations.
- It takes 2 minutes to reach the next station for trains going in east-west direction and 3 minutes to reach the next station for trains going in north-south direction.
- From each terminal station, the first train starts at 6 am; the last trains leave the terminal stations at midnight.
- during the service hours, there are metro service every 15 minutes in the north-south lines and every 10 minutes in the east-west lines.
- A train must rest for at least 15 minutes after completing a trip at the terminal station, before it can undertake the next trip in the reverse direction.
First we need to find the time taken from all terminals to all junctions through stations.
M → R = 2 + 2 + 2 + 2(3 stations gap is 4) + 3(every station stop ) = 11 min
P → T = 2 + 2 + 2 + 2 + 3 (same as above) = 11 min
R → S = 2 + 2 + 2+ 2 + 2 + 2 + 2 + 2 + 2 + 2(9 stations so gap is 10) + 9(9 stations ) = 20 min + 9 min = 29 min
T → V = symmetrical as R → S = 20 + 9 = 29 min
S → N = 2 + 2 + 2 + 2 + 2 + 2 + 5 = 12 + 5 = 17 min
V → Q = 12 + 5 = 17 min
A → R = 3 + 3 + 3 + 2 = 11 min
C → S = 3 + 3 + 3 + 2 = 11 min
R → T = 3 + 3 + 3 + 3 + 3 = 15 min
S → V = 3 + 3 + 3 + 3 + 3 = 15 min
T → B = 3 + 3 + 3(for north south direction train takes 3 minutes) + 2 = 11 min
V → D = 3 + 3 + 3 + 2 = 11 min
Travelling time between S and R
= ( 10 × 2 ) + ( 9 × 1 ) = 29
= (10×2)+(9×1) = 29 minutes
There is a stoppage of 2 minutes at R
Travelling time between R and B
= ( 7 × 3 ) + ( 1 × 2 ) + ( 5 × 1 ) = 28
= (7×3)+(1×2)+(5×1)=28 minutes
In the north-south direction, the first train from A arrives at R at time = 6 am + ( 3 × 3 ) + (2×1) = 6:11 am.
Since R is a junction so this train will halt for 2 minutes at R and leave at 6:13.
Every 15 minutes, a train starts from A in the north-south direction
The last train that leaves A will be at 12:00 am and it will leave R at 12:13 am, so Haripriya must reach R till 12:13 am.
Travelling time between S and R
= ( 10 × 2 ) + ( 9 × 1 ) = 29
So Haripriya must board the train at S by 11:44 pm
In the east-west direction,
the first train from N arrives at S at time
= 6 am + ( 6 × 2 ) + ( 5 × 1 ) (6×2)+(5×1) = 6:17 am
Since S is a junction so this train will halt for 2 minutes at S and leave at 6:19.
Every 10 minutes, a train starts from N in the east-west direction
Therefore, Haripriya should board the train which leaves S at 11:39