How many households did Lahur meet on the second day?

	Met			Sold
	D1	D2	Tot	D1	D2	Tot
T
H
L

In this table we have in first three columns the number of households met by three salesmen on day 1 (D1) , day 2 (D2) and it's total

Also, the last three columns consist of number of products sold by three salesmen in day 1 , day 2 and it's total

Here T, H, L represents Tohri, Hokli and Lahur respectively.

	Met			Sold
	D1	D2	Tot	D1	D2	Tot
T			x			100
H			x			100
L			x			100

Clue 1 says.

Over the two days, all three of them met the same total number of households,

Let the total number of houses they met be "x"

and each of them sold a total of 100 items.

=> total number of products sold by each of them is 100

	Met			Sold
	D1	D2	Tot	D1	D2	Tot
T			2y			100
H			2y			100
L	y	y	2y	50	50	100

Clue 2 says,

On both days, Lahur met the same number of households and sold the same number of items.

=> Lahur sold $50$ products each in day 1 and day2.

Also, let the number of household met by lahur be "y"

=> total number of households met by him = 2y

=> total number of households met by each salesmen = 2y (according to clue 1 )

	Met			Sold
	D1	D2	Tot	D1	D2	Tot
T	y - 15	y + 15	2y			100
H			2y			100
L	y	y	2y	50	50	100

Using clue 4,

Tohri met 30 more households on the second day than on the first day.

Let Tohri met "a" households on day 1

=> he will meet "a + 30 " households on day 2

=> a + a + 30 = 2y

=> 2a + 30 = 2y

=> a = y - 15

Therefore, households met by Tohri on day 1 = y - 15

and, on day 2 = y - 15 + 30 = y + 15

	Met			Sold
	D1	D2	Tot	D1	D2	Tot
T	y - 15	y + 15	2y			100
H	2y -1	1	2y	100	0	100
L	y	y	2y	50	50	100

Using clue 3,

Hokli could not sell any item on the second day because the first household he met on that day complained against him.

=> Hokli sold $'0'$ products on D2

Therefore, he sold all 100 items on D1 itself.

Also, he got complained in the very first household on the second day

=> he visited only $'1'$ house on day 2

=> he visited $2y - 1$ households on day 1.

	Met			Sold
	D1	D2	Tot	D1	D2	Tot
T	10	40	50	40	60	100
H	49	1	50	100	0	100
L	25	25	50	50	50	100

Clue 6 says,

Tohri's success rate was twice that of Lahur's on the first day, and it was 75% of Lahur's on the second day.

let the number of products sold by Tohri on D1 be $'x'$

we know, success rate of a salesman for a day is defined as the ratio of the number of items sold to the number of households met on that day

=> $x / (y -15) = (50 / y) *2$

=> $xy = 100(y–15)$.

=> $4x(100–x) = 150(y+15)$

=> $400y – 4xy = 150(y+15)$

=> $400y – 4*100(y–15) = 150(y+15) 400 * 15 = 150 (y+15)$.

therefore, $y = 25$

=> $x = 40$

put all the values of y and x in the table.

	Met			Sold
	D1	D2	Tot	D1	D2	Tot
T	10	40	50	40	60	100
H	49	1	50	100	0	100
L	25	25	50	50	50	100

The number of households Lahur met on the second day = 25

Hence, between 21 and 29