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A solution, of volume 4040 litres, has dye and water in the proportion 2:32: 3. Water is added to the solution to change this proportion to 2:52: 5. If one-fourths of this diluted solution is taken out, how many litres of dye must be added to the remaining solution to bring the proportion back to 2:32: 3?

Entered answer:

Solution

✅ Correct Answer: 8

We start with 40 litres where dye and water are in the ratio 2:3.

When we have a ratio like 2:3, it means:

Out of every 5 parts of solution, 2 parts are dye and 3 parts are water

Total parts = 2 + 3 = 5 parts

Calculating actual quantities:

Dye = 25×40=16\tfrac{2}{5} \times 40 = 16 litres

Water = 35×40=24\tfrac{3}{5} \times 40 = 24 litres

Check: 16 + 24 = 40 litres


When we add water, the amount of dye stays the same (16 litres).

The new ratio is 2:5 (dye:water), which means:

Total parts = 2 + 5 = 7 parts

Dye = 2 parts, Water = 5 parts

Since dye remains 16 litres and represents 2 parts:

1 part = 162=8\tfrac{16}{2} = 8 litres

Total solution = 7 parts = 7×8=567 \times 8 = 56 litres

Water = 5 parts = 5×8=405 \times 8 = 40 litres

Water added = 40 - 24 = 16 litres


Amount removed = 14×56=14\tfrac{1}{4} \times 56 = 14 litres

Remaining solution = 56 - 14 = 42 litres

When we remove part of a mixture, we remove it in the same ratio as the original mixture.

Since the ratio is still 2:5:

Dye remaining = 27×42=12\tfrac{2}{7} \times 42 = 12 litres

Water remaining = 57×42=30\tfrac{5}{7} \times 42 = 30 litres


Current state: 12 litres dye, 30 litres water

Target: Ratio of 2:3 (dye:water)

We're only adding dye, so water remains 30 litres.

If the final ratio is 2:3 and water = 30 litres:

Water represents 3 parts = 30 litres

1 part = 303=10\tfrac{30}{3} = 10 litres

Dye should be 2 parts = 2×10=202 \times 10 = 20 litres

Dye to be added = 20 - 12 = 8 litres


8 litres of dye must be added.

Always track what stays constant in each step:

Adding water: Dye stays constant while water is added

Removing solution: Ratio stays constant while solution is removed proportionally

Adding dye: Water stays constant while dye is added

This systematic approach prevents confusion and ensures accuracy.

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