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Alex invested his savings in two parts. The simple interest earned on the first part at 15%15 \% per annum for 44 years is the same as the simple interest earned on the second part at 12%12 \% per annum for 33 years. Then, the percentage of his savings invested in the first part is

Solution

✅ Correct Option: 4

Alex splits his savings into two parts and invests them at different interest rates. We need to find what percentage of his total savings went into the first part.

Key insight: When the simple interest earned from both parts is equal, we can find the ratio of the investments.


Let's say:

First part = xx

Second part = yy

Simple Interest Formula: SI=P×R×T100SI = \dfrac{P \times R \times T}{100}

Where P = Principal, R = Rate%, T = Time in years


The simple interest from both parts is equal:

First part: SI1=x×15×4100=60x100SI_1 = \dfrac{x \times 15 \times 4}{100} = \dfrac{60x}{100}

Second part: SI2=y×12×3100=36y100SI_2 = \dfrac{y \times 12 \times 3}{100} = \dfrac{36y}{100}

Since SI1=SI2SI_1 = SI_2:

60x100=36y100\dfrac{60x}{100} = \dfrac{36y}{100}


We cancel out the common factor of 100:

60x=36y60x = 36y

We divide both sides by 12 to simplify:

5x=3y5x = 3y

Finding the ratio: xy=35\dfrac{x}{y} = \dfrac{3}{5}


If x:y=3:5x : y = 3 : 5, then:

First part = 3 units

Second part = 5 units

Total savings = 3 + 5 = 8 units

Percentage of first part:

First partTotal savings×100=38×100=37.5%\dfrac{\text{First part}}{\text{Total savings}} \times 100 = \dfrac{3}{8} \times 100 = 37.5\%


Therefore, 37.5% of his savings was invested in the first part.

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