CATAlgebra > Easy3334.54.54.53.53.53.5444✅ Correct Option: 2Related questions:CAT 2020 Slot 2If xxx and yyy are positive real numbers satisfying x+y=102x + y = 102x+y=102, then the minimum possible value of 2601(1+1x)(1+1y)2601(1+\frac{1}{x})(1+\frac{1}{y})2601(1+x1)(1+y1) isCAT 2018 Slot 1While multiplying three real numbers, Ashok took one of the numbers as 737373 instead of 373737. As a result, the product went up by 720720720. Then the minimum possible value of the sum of squares of the other two numbers isCAT 2017 Slot 2The minimum possible value of the sum of the squares of the roots of the equation x2+(a+3)x−(a+5)=0x^{2}+(a+3) x-(a+5)=0x2+(a+3)x−(a+5)=0 is