Skip to main contentSkip to solution

Five students, including Amit, appear for an examination in which possible marks are integers between 00 and 50, both inclusive. The average marks for all the students is 3838 and exactly three students got more than 32. If no two students got the same marks and Amit got the least marks among the five students, then the difference between the highest and lowest possible marks of Amit is

Solution

✅ Correct Option: 2

We need to find the range of Amit's possible marks given several constraints.

We have:

55 students total (including Amit)

Marks range from 00 to 5050 (integers only)

Average marks =38= 38, so total marks =38×5=190= 38 \times 5 = 190

Exactly 33 students scored more than 3232

No two students have the same marks

Amit has the lowest marks among all five


To minimize Amit's marks, we need to maximize the marks of the other four students.

Since exactly 33 students scored more than 3232:

33 students scored 3333 or higher

22 students (including Amit) scored 3232 or lower

To maximize the others' marks:

Give the highest possible marks to the 33 students who scored above 3232: 5050, 4949, 4848

The fourth student gets the maximum possible while staying ≤32\leq 32: 3232

Amit gets: 190−(50+49+48+32)=190−179=11190 - (50 + 49 + 48 + 32) = 190 - 179 = 11


To maximize Amit's marks, we need to minimize the marks of the other four students while respecting all constraints.

Since Amit has the lowest marks:

Amit can score at most 3131 (anything higher would violate the "lowest marks" condition)

One other student must score 3232 (to satisfy the constraint that exactly 33 scored above 3232)

Now we need to distribute the remaining marks among the 33 students who scored above 3232:

Remaining total =190−31−32=127= 190 - 31 - 32 = 127

These 33 students must score more than 3232 and have different marks

The minimum they could theoretically score is 3333, 3434, 3535 (total =102= 102), but we need 127127.

So we have an extra 127−102=25127 - 102 = 25 marks to distribute.

One valid distribution: 3333, 4545, 4949 (check: 33+45+49=12733 + 45 + 49 = 127 ✓)

This gives us the maximum possible marks for Amit: 3131


Difference == Maximum −- Minimum =31−11=20= 31 - 11 = 20

The constraint "exactly 33 students scored more than 3232" is crucial - it means exactly 22 students scored 3232 or below. Since Amit has the lowest marks, this severely limits his possible range while keeping the total at 190190.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question