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Ankita is twice as efficient as Bipin, while Bipin is twice as efficient as Chandan. All three of them start together on a job, and Bipin leaves the job after 20 days. If the job got completed in 60 days, the number of days needed by Chandan to complete the job alone, is

Entered answer:

Solution

✅ Correct Answer: 340

Ankita is twice as efficient as Bipin, and Bipin is twice as efficient as Chandan.

Assuming Chandan's efficiency =1= 1 unit/day:

Bipin's efficiency =2= 2 units/day

Ankita's efficiency =4= 4 units/day


All three work together for the first 20 days, then Bipin leaves. The remaining work is done by Ankita and Chandan for 60−20=4060 - 20 = 40 days.


Work done in the first 20 days (all three working):

=(4+2+1)×20= (4 + 2 + 1) \times 20

=7×20= 7 \times 20

=140= 140 units


Work done in the next 40 days (Ankita + Chandan only):

=(4+1)×40= (4 + 1) \times 40

=5×40= 5 \times 40

=200= 200 units


Total work =140+200=340= 140 + 200 = 340 units

Since Chandan does 11 unit/day:

Days for Chandan alone =3401=340= \dfrac{340}{1} = 340 days

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