If the total amount of money raised in $2014$ is Rs. $12$ crores, then which of the following is not possible?

In this table we will try to fill the amount raised by each firm in it's year of existence.

Also we know each firm raised 1cr in first and last year of existence which we can fill from the question.

Let's first start with C,

The pattern looks as follows: 1, ..., 1

1. Let us assume there are 2 gaps between

=> a + b = 7 (Not possible)

as maximum case would be 1, 3, 2, 1

2. Let us assume there are 3 gaps between

=> a + b + c = 7

the minimum case possible is 1, 2, 3, 2, 1 => Satisfies

3. if there are 4 gaps

=> a + b + c + d = 7

=> no case will satisfy => Not possible

Consider D:

The pattern looks as follows: 1, a, b, c, 1

=> a + b + c = 8

1. When a = 2 and c = 2 => b = 4

=> 2, 4, 2 => Satisfies.

2. When a = 2 and c = 3, b should be 3 (Not satisfying)

3. When a = 3 and c = 3, b should be 2 (Not satisfying)

Therefore only possible case is 1, 2, 4, 2, 1.

Consider A:

It raised money for 8 years

=> The raising pattern looks like follows: 1, a, b, c, d, e, f, 1

Also a + b + c + d + e + f = 21 - 2 = 19.

We can observe that 19/6 is slightly greater than 3

=> The average amount raised should be around 3.

1. If a = 3 and f = 3

=> b + c + d + e = 13 (not possible)

as the minimum case would be (4, 5, 6, 4) => Not possible.

2. If a = 3 and f = 2

=> b + c + d + e = 14 (not possible)

as the minimum case would be (4, 5, 4, 3) => Not possible.

3. if a = 2 and f = 2

=> b + c + d + e = 15

the minimum case is (3, 4, 5, 3) or (3, 5, 4, 3) which gives a sum of 15.

Therefore there are 2 possible case for A

1. • 1, 2, 3, 4, 5, 3, 2, 1
2. • 1, 2, 3, 5, 4, 3, 2, 1

Consider B:

The patterns looks as follows: 1, a, b, 1

1. If a = 2,

b has to be equal to 3 to satisfy

2. if a = 3

b has to be equal to 2 to satisfy

Therefore 2 possible cases for B -

1. 1, 2, 3, 1

2. 1, 3, 2, 1

Consider E:

The pattern looks as follows: 1,.....,1

For 1 or 2 gaps, we can't get a sum of 11.

Assume 3 gaps

=> a + b + c = 11,

the maximum case is 3, 5, 3 => Satisfies.

Now, assume 4 gaps

=> a + b + c + d = 11,

the minimum case is 2, 3, 4, 2 or 2, 4, 3, 2 which satisfies

and 2 + 3 + 4 + 2 = 11.

The possible cases for E are:

1. 1, 3, 5, 3, 1

2. 1, 2, 3, 4, 2, 1

3. 1, 2, 4, 3, 2, 1

The possible cases for E are:

1. 1, 3, 5, 3, 1

2. 1, 2, 3, 4, 2, 1

3. 1, 2, 4, 3, 2, 1

If total amount raised in $2014=$ Rs. $12$ crores

$\Rightarrow$ amount raised by Bzygoo in $2014$ = Rs. $3$ crores

$\Rightarrow$ amount raised by Bzygoo in $2013$ = Rs $2$ crores

Also, amount raised by Elavalaki in $2013$ = Rs $3$ crore or Rs $4$ crores

Hence, Bzygoo raised the same amount of money as Elavalaki in 2013, it is not possible