Who attains the maximum total score?

2 day average through day 2 to day 5.

From table 2,

Let the total score of day 1, day 2, day 3, day 4, and day 5 are d1, d2, d3, d4, and d5, respectively.

The table shows that, the average of two days, d1 and d2 is 15,

then the average of two days d2 and d3 is 15.5, and so on (as given in the set).

d1+d2 = 30 ... (1),

d2+d3 = 31 ... (2),

d3+d4 = 32 .... (3),

d4+d5 = 34 ... (4)

clue 2 says,

The total score on Day 3 is the same as the total score on Day 4.

i.e., d3 = d4

And we know, d3 + d4 = 32

=> d3 = d4 = 16

Now using previous equations,

we know d2+ d3 = 31 => d2 = 15

and, d1 + d2 = 30 => d1 = 15

and , d4 + d5 = 34 => 18

Clue 1 says,

Chatur always scores in multiples of 3. His score on Day 2 is the unique highest score in the competition.

therefore, chatur score on day 2 will be a multiple of 3 and also unique highest

which can only be 9.

(as it is given that each participant randomly picks up a ball numbered between 1 and 9, therefore, the highest score can't be greater then 9.)

=> No other person scored 9 or more then 9 on 5 days.

Continuing with Clue 1,

Chatur's minimum score is observed only on Day 1, and it matches Akhil's score on Day 4.

Now, we already know that his score is a multiple of 3

therefore, his minimum score will be 3.

And the same will be Akhil's score on day 4.

Also question says that Chatur has a unique minimum and maximum score.

which we found to be 3 and 9

So, the only multiple of 3 between them is 6, which will be his score on other days.

From which we can find Bimal's score on day 4 to be

Akhil + bimal + chatur = 16 (on day 4)

=> bimal = 16 - 6 - 3

=> bimal = 7

From the second table we know, we see that the rank of Bimal and Akhil is the same on day 3, which is 2.

Hence, The score obtained by Akhil and Bimal is the same.

Let the score be x.

Therefore, 6+2x = 16

=> x = 5

The rank of Chatur on Day 5 is 2, and the rank of Bimal is 1

which implies the score obtained by Bimal will be more than Chatur.

Chatur had score of 6, also we know that maximum score is 9

Therefore, Bimal's score on day 5 = 7/8

And accordingly subtracting both Chatur's and Bimal's score on day 5

we will get Akhil's score to be - 5/4

Clue 3 says, Bimal's scores are the same on Day 1 and Day 3.

Hence, the score obtained by Bimal on Day 1 is 5

which implies The score obtained by Akhil is 7 on Day 1

From Table 2, we can see that the rank of Bimal is 3 on Day 2, and the rank of Akhil is 2 on Day 2.

Hence, the score of Bimal will be lower than Akhil on Day 2.

Let the score of Akhil be a, and the score of Bimal be b.

Then 9+a+b = 15, and a > b

=> a+b =6, and a> b

Hence, the value of a can be 4/5, and the value of b can be 2/1.

Chatur attains the maximum possible score