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Ravi is driving at a speed of 4040 km/h on a road. Vijay is 5454 meters behind Ravi and driving in the same direction as Ravi. Ashok is driving along the same road from the opposite direction at a speed of 5050 km/h and is 225225 meters away from Ravi. The speed, in km/h, at which Vijay should drive so that all the three cross each other at the same time, is

Solution

✅ Correct Option: 1
Vijay (?) --- 54m --- Ravi (40km/hr) -------- 225m -------- Ashok (50km/hr)
    →                       →                                      ←

All three drivers need to meet at the same point at the same time. Let us find when and where this happens.


Since Ravi and Ashok are driving towards each other, their speeds add up.

When two objects move towards each other, their relative speed = sum of individual speeds.

Ravi's speed: 40 km/h

Ashok's speed: 50 km/h

Combined speed: 40 + 50 = 90 km/h

Distance between them: 225 m

To convert km/h to m/s, multiply by 518\tfrac{5}{18}

90 km/h = 90 × 518\tfrac{5}{18} = 25 m/s

Time for Ravi and Ashok to meet:

Time=DistanceSpeed=225 m25 m/s=9 seconds\text{Time} = \tfrac{\text{Distance}}{\text{Speed}} = \tfrac{225 \text{ m}}{25 \text{ m/s}} = 9 \text{ seconds}


In these same 9 seconds, Vijay must catch up to Ravi's position.

Vijay is currently 54 m behind Ravi. For them to meet, Vijay must travel 54 m more than Ravi travels in 9 seconds.

This means Vijay's speed must be higher than Ravi's speed.


Let Vijay's speed = V km/h

Relative speed between Vijay and Ravi = (V - 40) km/h

This is because they're moving in the same direction.

Converting to m/s: (V - 40) km/h = (V - 40) × 518\tfrac{5}{18} m/s

Distance equation:

Distance=Speed×Time\text{Distance} = \text{Speed} \times \text{Time}

54=(V−40)×518×954 = (V - 40) \times \tfrac{5}{18} \times 9


54=(V−40)×5×91854 = (V - 40) \times \tfrac{5 \times 9}{18}

54=(V−40)×451854 = (V - 40) \times \tfrac{45}{18}

54=(V−40)×5254 = (V - 40) \times \tfrac{5}{2}

54×25=V−4054 \times \tfrac{2}{5} = V - 40

1085=V−40\tfrac{108}{5} = V - 40

21.6=V−4021.6 = V - 40

V=40+21.6=61.6 km/hV = 40 + 21.6 = 61.6 \text{ km/h}


Therefore, Vijay should drive at 61.6 km/h.

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