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In a company, 20%20\% of the employees work in the manufacturing department. If the total salary obtained by all the manufacturing employees is one-sixth of the total salary obtained by all the employees in the company, then the ratio of the average salary obtained by the manufacturing employees to the average salary obtained by the non-manufacturing employees is

Solution

✅ Correct Option: 2

20% of all employees work in manufacturing

Hence, ratio of manufacturing employees to non-manufacturing employees =1:4= 1:4


Manufacturing employees' total salary = 1/6 of company's total salary

Hence, ratio of manufacturing employees (salary) to non-manufacturing employees (salary) =1:5= 1:5


Average salary of a department = Total salary of a department ÷ Number of employees in that department

Average salary of manufacturing employees =11=1=\dfrac{1}{1} = 1

Average salary of non-manufacturing employees =54=\dfrac{5}{4}


Ratio == (Average salary of manufacturing) :: (Average salary of non-manufacturing)

=1:54= 1 : \dfrac{5}{4}

Multiplying both sides by 44:

=4:5= \boxed{4:5}

Therefore, the ratio is 4:5


This result tells us that manufacturing employees earn lower average salaries than non-manufacturing employees. Even though manufacturing employees make up 20% of the workforce, they only receive 1/6 ≈ 16.67% of the total salary, indicating their individual salaries are lower on average.

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