In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali. After a review, the score of each of them increased by . The revised scores of Anjali, Mohan, and Rama were in the ratio . Then Anjali's score exceeded Rama's score by
In an examination, Rama's score was one-twelfth of the sum of the scores of Mohan and Anjali. After a review, the score of each of them increased by . The revised scores of Anjali, Mohan, and Rama were in the ratio . Then Anjali's score exceeded Rama's score by
Solution
Let us represent the original scores with variables:
Rama's original score = R
Mohan's original score = M
Anjali's original score = A
Rama's score was one-twelfth of the sum of Mohan's and Anjali's scores:
After each score increased by 6, the ratio became 11:10:3 (Anjali : Mohan : Rama).
When we have a ratio like 11:10:3, it means:
Anjali's revised score = 11x (for some value x)
Mohan's revised score = 10x
Rama's revised score = 3x
Since each score increased by 6, the original scores were:
Anjali's original score = 11x - 6
Mohan's original score = 10x - 6
Rama's original score = 3x - 6
Substituting into our first equation:
Now we can find the original scores:
Anjali's original score = 11x - 6 = 11(4) - 6 = 44 - 6 = 38
Rama's original score = 3x - 6 = 3(4) - 6 = 12 - 6 = 6
The difference = 38 - 6 = 32
Therefore, Anjali's score exceeded Rama's score by 32.