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A glass is filled with milk. Two-thirds of its content is poured out and replaced with water. If this process of pouring out two-thirds the content and replacing with water is repeated three more times, then the final ratio of milk to water in the glass, is

Solution

✅ Correct Option: 2

For any dilution problem where you remove fraction p and repeat n times:

Remaining original substance = (1−p)n(1-p)^n

Here: p=23p = \dfrac{2}{3}, n=4n = 4, so remaining milk = (1−23)4=(13)4=181\left(1-\frac{2}{3}\right)^4 = \left(\frac{1}{3}\right)^4 = \dfrac{1}{81}

Answer - 1:801 : 80


Longer Explaination:

Initially: Glass is 100% milk

Each time: Remove 2/3 of current content → Add water to fill the glass

The key insight: When we remove 2/3 of the mixture, we keep 1/3 of whatever was there before.


Let us trace through each step:

After 1st operation:

Remove 2/3 of pure milk

Keep 1/3 of original milk = 13\dfrac{1}{3} milk

Add water to fill = 23\dfrac{2}{3} water

After 2nd operation:

Remove 2/3 of current mixture (which has 13\dfrac{1}{3} milk and 23\dfrac{2}{3} water)

Keep 1/3 of current mixture

Milk remaining = 13×13=19\dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{9} of original milk

After 3rd operation:

Milk remaining = 13×19=127\dfrac{1}{3} \times \dfrac{1}{9} = \dfrac{1}{27} of original milk

After 4th operation:

Milk remaining = 13×127=181\dfrac{1}{3} \times \dfrac{1}{27} = \dfrac{1}{81} of original milk


After each operation, the milk fraction gets multiplied by 13\dfrac{1}{3}.

After 4 operations: Milk fraction = (13)4=181\left(\frac{1}{3}\right)^4 = \dfrac{1}{81}

Why this works: Each time we remove 2/3 and keep 1/3, we're essentially multiplying the milk concentration by 13\dfrac{1}{3}.


Since the glass is always full:

Milk fraction = 181\dfrac{1}{81}

Water fraction = 1−181=80811 - \dfrac{1}{81} = \dfrac{80}{81}

Final ratio = Milk : Water = 181:8081\dfrac{1}{81} : \dfrac{80}{81}

Simplifying by multiplying both parts by 81:

Milk : Water = 1 : 80

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