A glass is filled with milk. Two-thirds of its content is poured out and replaced with water. If this process of pouring out two-thirds the content and replacing with water is repeated three more times, then the final ratio of milk to water in the glass, is
A glass is filled with milk. Two-thirds of its content is poured out and replaced with water. If this process of pouring out two-thirds the content and replacing with water is repeated three more times, then the final ratio of milk to water in the glass, is
Solution
For any dilution problem where you remove fraction p and repeat n times:
Remaining original substance =
Here: , , so remaining milk =
Answer -
Longer Explaination:
Initially: Glass is 100% milk
Each time: Remove 2/3 of current content → Add water to fill the glass
The key insight: When we remove 2/3 of the mixture, we keep 1/3 of whatever was there before.
Let us trace through each step:
After 1st operation:
Remove 2/3 of pure milk
Keep 1/3 of original milk = milk
Add water to fill = water
After 2nd operation:
Remove 2/3 of current mixture (which has milk and water)
Keep 1/3 of current mixture
Milk remaining = of original milk
After 3rd operation:
Milk remaining = of original milk
After 4th operation:
Milk remaining = of original milk
After each operation, the milk fraction gets multiplied by .
After 4 operations: Milk fraction =
Why this works: Each time we remove 2/3 and keep 1/3, we're essentially multiplying the milk concentration by .
Since the glass is always full:
Milk fraction =
Water fraction =
Final ratio = Milk : Water =
Simplifying by multiplying both parts by 81:
Milk : Water = 1 : 80