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Sam can complete a job in 20 days when working alone. Mohit is twice as fast as Sam and thrice as fast as Ayna is the same job. The undertake a job with an arrangement where Sam and Mohit work together on the first day, Sam and Ayna on the second day, Mohit and Ayna on the third day, and this three-day pattern is repeated till the work gets completed. Then, the fraction of total work done by Sam is

Solution

✅ Correct Option: 2

Sam completes the job alone in 20 days, so his work rate = 120\frac{1}{20} of the job per day.

If someone completes a job in 20 days, they complete 120\frac{1}{20} of the job each day. This is a fundamental concept in work problems.


We are told:

Mohit is 2 times as fast as Sam

Mohit is 3 times as fast as Ayna

Let's convert this to ratios:

M:S=2:1M : S = 2 : 1 (Mohit : Sam)

M:A=3:1M : A = 3 : 1 (Mohit : Ayna)

To combine these ratios, we need the same value for Mohit in both ratios.

From M:S=2:1M : S = 2 : 1, we can write this as M=6,S=3M = 6, S = 3

From M:A=3:1M : A = 3 : 1, we can write this as M=6,A=2M = 6, A = 2

We need a number that's divisible by both 2 and 3. The smallest such number is 6.

Therefore: S:M:A=3:6:2S : M : A = 3 : 6 : 2


Since Sam's efficiency is 3 units and he takes 20 days to complete the job:

Total work = Sam's daily work × Days taken

= 3 × 20

= 60 units

This means:

Sam works at 3 units per day

Mohit works at 6 units per day

Ayna works at 2 units per day


The work pattern repeats every 3 days:

Day 1: Sam + Mohit = 3+6=93 + 6 = 9 units

Day 2: Sam + Ayna = 3+2=53 + 2 = 5 units

Day 3: Mohit + Ayna = 6+2=86 + 2 = 8 units

Work completed in each 3-day cycle = 9+5+8=229 + 5 + 8 = 22 units


Let's see how the work progresses:

After 3 days: 22 units completed

After 6 days: 22×2=4422 × 2 = 44 units completed

Remaining work: 60−44=1660 - 44 = 16 units

Continuing the pattern:

Day 7 (Sam + Mohit): 9 units → Total: 44+9=5344 + 9 = 53 units

Day 8 (Sam + Ayna): 5 units → Total: 53+5=5853 + 5 = 58 units

Day 9 (Mohit + Ayna): Only need 2 more units to reach 60 → Work completed on Day 9


Sam works on the first 2 days in each cycle (total cycles = 3).

Sam's total working days = 2 ×\times 3 = 6 days

Sam's total work = 6 days × 3 units per day = 18 units


Fraction of work done by Sam = Sam’s workTotal work=1860=310\frac{\text{Sam's work}}{\text{Total work}} = \frac{18}{60} = \frac{3}{10}

In work problems with rotating patterns, we always track who works on which days and calculate their total contribution.

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