CATAlgebra > Hard[3,10]∪[5,26][3,\sqrt{10}]\cup[5,\sqrt{26}][3,10]∪[5,26][3,10]∪[4,17]∪{6}[3,\sqrt{10}]\cup[4,\sqrt{17}]\cup\{6\}[3,10]∪[4,17]∪{6}[3,10)∪[5,26)∪{6}[3,\sqrt{10})\cup[5,\sqrt{26})\cup\{6\}[3,10)∪[5,26)∪{6}(4,18)∪[5,27)∪{6}(4,\sqrt{18})\cup[5,\sqrt{27})\cup\{6\}(4,18)∪[5,27)∪{6}✅ Correct Option: 3Related questions:2025 Slot 2Let f(x)=x(2x−1)f(x) = \dfrac{x}{(2x-1)}f(x)=(2x−1)x and g(x)=x(x−1)g(x) = \dfrac{x}{(x-1)}g(x)=(x−1)x. Then, the domain of the function h(x)=f(g(x))+g(f(x))h(x) = f(g(x)) + g(f(x))h(x)=f(g(x))+g(f(x)) is all real numbers exceptCAT 2020 Slot 3If f(x+y)=f(x)f(y)f(x + y) = f (x) f (y)f(x+y)=f(x)f(y) and f(5)=4f(5) = 4f(5)=4, then f(10)−f(−10)f (10) - f (-10)f(10)−f(−10) is equal toCAT 2017 Slot 1If f(x)=5x+23x−5f(x) = \frac{5x + 2}{3x - 5}f(x)=3x−55x+2 and g(x)=x2−2x−1g(x) = x^2 - 2x - 1g(x)=x2−2x−1, then the value of g(f(f(3)))g(f(f(3)))g(f(f(3))) is