Skip to main contentSkip to solution

For a 4-digit number (greater than 1000), sum of the digits in the thousands, hundreds, and tens places is 15. Sum of the digits in the hundreds, tens, and units places is 16. Also, the digit in the tens place is 6 more than the digit in the units place. The difference between the largest and smallest possible value of the number is

Solution

✅ Correct Option: 2

Let the 4-digit number be abcdabcd, where aa is the thousands digit, bb is the hundreds digit, cc is the tens digit, and dd is the units digit.

From the given conditions:

a+b+c=15a + b + c = 15 --- (1)

b+c+d=16b + c + d = 16 --- (2)

c=d+6c = d + 6 --- (3)


Since c=d+6c = d + 6 and c≤9c \leq 9, we get d≤3d \leq 3, so dd can be 0,1,2,0, 1, 2, or 33.

Substituting c=d+6c = d + 6 in Equation (2):

b+(d+6)+d=16b + (d + 6) + d = 16

b=10−2db = 10 - 2d

Substituting b=10−2db = 10 - 2d and c=d+6c = d + 6 in Equation (1):

a+(10−2d)+(d+6)=15a + (10 - 2d) + (d + 6) = 15

a=d−1a = d - 1


Testing all possible values of dd:

dda=d−1a = d - 1b=10−2db = 10 - 2dc=d+6c = d + 6NumberValid?
0-1106-No, aa is negative and bb is not a single digit
10870871No, a=0a = 0 makes it a 3-digit number
21681682Yes
32492493Yes

Since dd can only range from 0 to 3, the only valid numbers are 16821682 and 24932493.


Difference =2493−1682=811= 2493 - 1682 = 811

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question