Two types of tea, and , are mixed and then sold at Rs. per kg. The profit is if A and B are mixed in the ratio , and if this ratio is . The cost prices, per kg , of and are in the ratio
Two types of tea, and , are mixed and then sold at Rs. per kg. The profit is if A and B are mixed in the ratio , and if this ratio is . The cost prices, per kg , of and are in the ratio
Solution
When dealing with mixture problems involving profit percentages, we need to connect three key concepts:
Cost Price (CP): What we pay to buy the tea
Selling Price (SP): What we sell the tea for
Profit Percentage: The extra money we make as a percentage of cost price
If profit is 10%, then SP = CP × (1 + 10/100) = CP × 1.1
Let's call the cost prices of tea A and B as Ca and Cb respectively.
Given Information:
Selling price of mixture = Rs. 40 per kg (constant in both cases)
Case 1: A:B = 3:2 ratio gives 10% profit
Case 2: A:B = 2:3 ratio gives 5% profit
When we mix 3 kg of A with 2 kg of B, we get 5 kg of mixture.
Cost of this mixture = 3Ca + 2Cb
Average cost per kg = (3Ca + 2Cb)/5
Since we make 10% profit:
40 = [(3Ca + 2Cb)/5] × 1.1
40/1.1 = (3Ca + 2Cb)/5 ---------(1)
When we mix 2 kg of A with 3 kg of B, we get 5 kg of mixture.
Cost of this mixture = 2Ca + 3Cb
Average cost per kg = (2Ca + 3Cb)/5
Since we make 5% profit:
40 = [(2Ca + 3Cb)/5] × 1.05
40/1.05 = (2Ca + 3Cb)/5 ---------(2)
Instead of solving each equation individually, let's use a smart approach by dividing equation (1) by equation (2):
The 40s and 5s cancel out:
Converting to fractions (since 1.05 = 21/20 and 1.1 = 22/20):
So:
Cross-multiplying:
Expanding both sides:
Collecting like terms:
Therefore:
The cost prices of tea A and B are in the ratio 19:24.
This makes sense because tea A is cheaper than tea B, so when we use more of A (3:2 ratio), we get higher profit (10%) compared to when we use more of B (2:3 ratio gives only 5% profit).