Solution
Understanding the set :-
It’s a classic logical reasoning + Venn diagram problem.
- There are 500 students in total in a survey.
- Two proposals:
A: Dress code by college authorities
B: Allow multinational food franchises
- Two candidates for student union president:
a) Sunita
b) Ragini
- Each student:
Can support any, none, or both proposals (A and/or B).
Everyone must prefer only one candidate: Sunita or Ragini
This set gives you enough interconnected clues to figure out:
a) How many supported both A and B.
b)How many supported only one or none.
c)The exact preference breakdowns of each student group.
Lets find the thought process to solve this kind of sets.
Total number of students surveyed= 500
Every student prefers one of the two candidates. Ragini(R) and Sunita(S).
Thus, R+S=500.
Clue 2 says,
Among the 200 students who preferred Sunita
=> The number of students who support Sunita(S)=200
and, The number of students who supported Ragini(R)=300.
Continuing with clue 2;
Among the 200 students who preferred Sunita as student union president, 80% supported proposal A.
=>
=> 160 students who supported Sunita also supported the proposal A.
Clue 3 says,
Among those who preferred Ragini, 30% supported proposal A.
We know, The number of students who supported Ragini(R)=300.
=>
=> 90 students who supported Ragini also supported proposal A.
Clue 4 says,
20% of those who supported proposal B preferred Sunita.
We know, 250 students supported proposal B. (clue 1)
=>
=> 50 students who supported Proposal B also supported Sunita.
Clue 6 says,
Every student who preferred Sunita and supported proposal B also supported proposal A.
We know, 50 students who supported Proposal B also supported Sunita
=> All those 50 students will also prefer proposal A.
=> There will be no student who prefer only Proposal B.
=> There will be students who prefer proposal A only.
=> There will be students who do not prefer any of the proposal.
Clue 7 says,
Among those who preferred Ragini, 20% did not support any of the proposals.
We know, The number of students who supported Ragini(R)=300.
=>
=> There are 60 students among those who prefer Ragini, who do not prefer any of proposal A and B
Clue 5 says,
40% of those who did not support proposal B preferred Ragini.
we know, 250 students supported proposal B.
=>
=> 100 people who preferred Ragini did not support proposal B
=> these 100 people will include those who -
-
only support proposal A.
-
Do not support any of proposal A or B.
Now, we know, there are 60 students among those who prefer Ragini, who do not prefer any of proposal A and B.
=> there will be people who prefer only proposal A.
Now, we know, There are 90 people who preferred proposal A for Ragini.
And, 40 people who preferred only proposal A
=> $90 - 40 = 50 people will support both A and B.
=> there will be people who preferred only proposal B.
Students who supported both proposals