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Three doctors, Dr. Ben, Dr. Kane and Dr. Wayne visit a particular clinic Monday to Saturday to see patients. Dr. Ben sees each patient for 10 minutes and charges Rs. 100/-. Dr. Kane sees each patient for 15 minutes and charges Rs. 200/-, while Dr. Wayne sees each patient for 25 minutes and charges Rs. 300/-.

The clinic has three rooms numbered 1, 2 and 3 which are assigned to the three doctors as per the following table.

Room No.Monday & TuesdayWednesday & ThursdayFriday & Saturday
1BenWayneKane
2KaneBenWayne
3WayneKaneBen

The clinic is open from 9 a.m. to 11.30 a.m. every Monday to Saturday.

On arrival each patient is handed a numbered token indicating their position in the queue, starting with token number 1 every day. As soon as any doctor becomes free, the next patient in the queue enters that emptied room for consultation. If at any time, more than one room is free then the waiting patient enters the room with the smallest number. For example, if the next two patients in the queue have token numbers 7 and 8 and if rooms numbered 1 and 3 are free, then patient with token number 7 enters room number 1 and patient with token number 8 enters room number 3.

The queue is never empty on one particular Saturday. Which of the three doctors would earn the maximum amount in consultation charges on that day?

Solution

✅ Correct Option: 4
Slide 1/2

Understanding the set :-

This set is a logical reasoning and scheduling problem

  1. Here we are given information about a clinic -

a) Open: Monday to Saturday

b) Time: 9:00 AM – 11:30 AM → 150 minutes total per day

  1. Also, we are given details of each doctor as -
DoctorTime per PatientCharge per Patient
Ben10 minutes₹100
Kane15 minutes₹200
Wayne25 minutes₹300

=> So, in 150 minutes:

a) Ben can see 15 patients

b) Kane can see 10 patients

c) Wayne can see 6 patients

  1. There is a room schedule as -
Room No.Mon & TueWed & ThuFri & Sat
1BenWayneKane
2KaneBenWayne
3WayneKaneBen

So, the doctors rotate across rooms based on days.

  1. Also, there is a token system -

i) Patients enter the clinic and receive tokens (1, 2, 3, ...).

ii) When any doctor becomes free, the next patient in the queue goes in.

iii) If multiple rooms are free, patient with lowest token chooses the smallest numbered room.

Example:

If token 7 is next and rooms 1 and 3 are free, token 7 → Room 1

and, Token 8 → Room 3

Now, lets try to solve the set using these clues.

The queue is never empty on one particular Saturday it means all the doctor are working to their full capacity.

(i) Maximum number of patients that can be seen by Dr. Ben are 150/10=15150/10=15.

As charges of of Dr. Ben are 100/−100/-

So maximum amount in consultation charges earned by Dr. Ben are 15×100=1500/−15\times100 = 1500/-

(ii) Maximum number of patients that can be seen by Dr. Kane are 150/15=10150/15=10

As charges of of Dr. Kane are 200/−200/-

So maximum amount in consultation charges earned by Dr. Kane are 10×200=2000/−10\times200=2000/-

(iii) Maximum number of patients that can be seen by Dr. Dr. Wayne are 150/25=6150/25=6

As charges of of Dr. Wayne are 300/−300/-

So maximum amount in consultation charges earned by Dr. Ben are 6×300=1800/−6\times300 =1800/-

Hence among three doctors Dr. Kane would earn the maximum amount in consultation charges on Saturday.

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