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Amar, Akbar and Anthony are working on a project. Working together Amar and Akbar can complete the project in 11 year, Akbar and Anthony can complete in 1616 months, Anthony and Amar can complete in 22 years. If the person who is neither the fastest nor the slowest works alone, the time in months he will take to complete the project is

Entered answer:

Solution

✅ Correct Answer: 32

We have three workers with different combination timings:

Amar + Akbar together: 1 year = 12 months

Akbar + Anthony together: 16 months

Anthony + Amar together: 2 years = 24 months

We need to find how long the middle-speed worker takes alone.


When dealing with work problems, it's easier to think in terms of "units of work done per month" rather than "months to complete work."

Let's assume the total work = 48 units

48 is the LCM of 12, 16, and 24, making our calculations clean without fractions.

Now we can find each pair's work rate:

Amar + Akbar: 48÷12=448 \div 12 = 4 units/month

Akbar + Anthony: 48÷16=348 \div 16 = 3 units/month

Anthony + Amar: 48÷24=248 \div 24 = 2 units/month


If we add all three equations:

(Amar+Akbar)+(Akbar+Anthony)+(Anthony+Amar)=4+3+2=9(Amar + Akbar) + (Akbar + Anthony) + (Anthony + Amar) = 4 + 3 + 2 = 9 units/month

This simplifies to: 2(Amar+Akbar+Anthony)=92(Amar + Akbar + Anthony) = 9 units/month

Therefore: Amar+Akbar+Anthony=4.5Amar + Akbar + Anthony = 4.5 units/month

Now we can find each person's individual rate:

Anthony's rate = (Allthreetogether)−(Amar+Akbar)=4.5−4=0.5(All three together) - (Amar + Akbar) = 4.5 - 4 = 0.5 units/month

Amar's rate = (Allthreetogether)−(Akbar+Anthony)=4.5−3=1.5(All three together) - (Akbar + Anthony) = 4.5 - 3 = 1.5 units/month

Akbar's rate = (Allthreetogether)−(Anthony+Amar)=4.5−2=2.5(All three together) - (Anthony + Amar) = 4.5 - 2 = 2.5 units/month


Time = Total Work ÷ Work Rate

Anthony: 48÷0.5=9648 \div 0.5 = 96 months (slowest)

Amar: 48÷1.5=3248 \div 1.5 = 32 months (middle)

Akbar: 48÷2.5=19.248 \div 2.5 = 19.2 months (fastest)


The question asks for the time taken by the person who is "neither fastest nor slowest."

From our calculations:

Fastest: Akbar (19.2 months)

Middle: Amar (32 months)

Slowest: Anthony (96 months)

Therefore, the answer is 32 months.


In work problems involving multiple workers, we always:

  1. Convert all times to the same unit
  2. Use LCM for total work to avoid fractions
  3. Add all pair equations to find the sum of individual rates
  4. Subtract to find individual rates

This systematic approach works for any number of workers and any combination of given information.

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