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Bank AA offers 6%6 \% interest rate per annum compounded half yearly. Bank BB and Bank CC offer simple interest but the annual interest rate offered by Bank CC is twice that of Bank BB. Raju invests a certain amount in Bank B for a certain period and Rupa invests ₹10,000₹ 10,000 in Bank CC for twice that period. The interest that would accrue to Raju during that period is equal to the interest that would have accrued had he invested the same amount in Bank AA for one year. The interest accrued, in INR, to Rupa is

Solution

✅ Correct Option: 4

Given Information:

Bank A: 6% per annum compounded half yearly

Bank B: Simple interest at rate R%

Bank C: Simple interest at rate 2R% (twice Bank B's rate)

Investment Details:

Raju: Invests amount P in Bank B for time T

Rupa: Invests ₹10000 in Bank C for time 2T

Key Condition: Raju's interest from Bank B equals the interest he would earn from Bank A in 1 year.


Since Bank A compounds half yearly, we apply the compound interest formula:

Amount = Principal × (1+Rate100)n(1 + \frac{\text{Rate}}{100})^n

Here:

Principal = P

Rate per half year = 62\frac{6}{2} = 3%

Number of half years in 1 year = 2

Amount after 1 year = P×(1+3100)2P × (1 + \frac{3}{100})^2

= P×(1.03)2P × (1.03)^2

= P×1.0609P × 1.0609

Interest from Bank A = P×1.0609−PP × 1.0609 - P

= P×0.0609P × 0.0609


Raju's interest from Bank B = P×R×T100\frac{P × R × T}{100}


We know that Raju's interest from Bank B equals his potential interest from Bank A:

P×R×T100=P×0.0609\frac{P × R × T}{100} = P × 0.0609

Dividing both sides by P:

R×T100=0.0609\frac{R × T}{100} = 0.0609

Therefore: R×T=6.09R × T = 6.09

Key Insight: This relationship (R×T=6.09)(R × T = 6.09) is crucial for solving the rest of the problem.


Rupa's Investment Details:

Principal = ₹10000

Rate = 2R% (twice Bank B's rate)

Time = 2T (twice Raju's period)

Rupa's Interest = 10000×2R×2T100\frac{10000 × 2R × 2T}{100}

= 10000×4RT100\frac{10000 × 4RT}{100}

= 10000×4×6.09100\frac{10000 × 4 × 6.09}{100} [Since RT=6.09RT = 6.09]

= 10000×24.36100\frac{10000 × 24.36}{100}

= ₹2436


Rupa's interest = ₹2436

Method Summary: We recognized that the compound interest calculation from Bank A gives us the relationship RT=6.09RT = 6.09, which we then used to find Rupa's simple interest with the doubled rate and doubled time period.

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