At their usual efficiency levels, and together finish a task in days. If had worked half as efficiently as she usually does, and had worked thrice as efficiently as he usually does, the task would have been completed in days. How many days would take to finish the task if she works alone at her usual efficiency?
At their usual efficiency levels, and together finish a task in days. If had worked half as efficiently as she usually does, and had worked thrice as efficiently as he usually does, the task would have been completed in days. How many days would take to finish the task if she works alone at her usual efficiency?
Solution
We have two workers, A and B, with different efficiency levels. We need to find how long A takes to complete the task alone.
Given information:
A and B together finish the task in 12 days (at usual efficiency)
If A works at half efficiency and B works at triple efficiency, they finish in 9 days
Find: Days for A to complete the task alone
We think about work rates in terms of "units of work per day":
We let A normally do units per day
We let B normally do units per day
We choose for A because this makes the math cleaner when A works at "half efficiency" - it becomes just units per day.
Scenario 1: Normal efficiency
A does units/day, B does units/day
Together they complete the task in 12 days
Total work = units
Scenario 2: Changed efficiency
A works at half efficiency = units/day
B works at triple efficiency = units/day
Together they complete the task in 9 days
Total work = units
The total work is the same in both scenarios, so:
Expanding both sides:
Therefore:
Since , we can choose any convenient value. We use .
This gives us:
A's normal rate = units per day
B's normal rate = unit per day
Total work = units
If A works alone at her usual efficiency:
Time = days
A would take 18 days to finish the task alone.